c^2+4c-5=0

Solution for c^2+4c-5=0 equation:

Simplifying
c2 + 4c + -5 = 0

Reorder the terms:
-5 + 4c + c2 = 0

Solving
-5 + 4c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -1c)(1 + -1c) = 0

Subproblem 1
Set the factor '(-5 + -1c)' equal to zero and attempt to solve:

Simplifying
-5 + -1c = 0

Solving
-5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1c = 0 + 5
-1c = 0 + 5

Combine like terms: 0 + 5 = 5
-1c = 5

Divide each side by '-1'.
c = -5

Simplifying
c = -5
Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Solution
c = {-5, 1}